7z+2x=109 5z + 3x = 81
7z+2x=109
7z+2x-2x=109-2x
7z=109-2x
7z/7=109-2x/7
z = 109/7-(2 x)/7
5z + 3x = 81 solve for x
5(109/7-2x/7)+3x=81
5(109/7-2x/7)+3x=81
5(109/7-2x/7)+21x/7=81
5(109-2x)+21x/7=81
545-10x+21x/7=81
545+11x/7=81
(545+11x/7_*7=81*7
545+11x=567
545-545+11x=567-545
11x=22
11x/11=22/11
x=2
solve for z
7z+2x=109
7z+2(2)=109
7z+4=109
7z+4-4=109-4
7z=105
7z/7=205/7
z=15