Math (7y^4 - 8y^2 + 6) - (5y^4 - 2 + 4y) Asked by AnneS2 12 years ago 9/27/2013 7:15 AM Last updated by anonymous 12 years ago 9/28/2013 11:08 AM
(7y^4 - 8y^2 + 6) - (5y^4 - 2 + 4y) 7y^4 - 8y^2 + 6 - 5y^4 + 2 - 4y 7y^4 - 5y^4 - 8y^2 - 4y + 6 + 2 2y^4 - 8y^2 - 4y + 8