Math

7k^2 -6k+3=3 Solve

Asked by AnneS2 on 15 May 05:23

Last updated by anonymous on 16 May 14:35

1 Answers

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Answered by CherieS on 16 May 14:35

7k^2 -6k+3=3

7k^2 -6k+3-3=3 -3

7k^2 -6k=0

k (7 k-6) = 0

Solve:

k=0

Solve:

(7 k-6) = 0

7k-6+6=0+6

7k=6

7k/7=6/7

k=6/7