Math

6z^2 -52z+80=0

Asked by AnneS2 on 24 Apr 03:36

Last updated by anonymous on 26 Apr 22:42

1 Answers

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Answered by CherieS on 26 Apr 22:42

6z^2 -52z+80=0

2(3z^2-26z+40)

2(z )(3z ) ( -2)( -20)

2(z-2)(3z-20)=0

Check:

2(z-2)(3z-20)

2 (z)(3z) (z)(-20) (-2)(3z)(-2)(-20)

2 (3z^2 -20z -6z +40)

2 (3z^2 -26z +40)