Math

64x^2 + 16x + 1 = 0

Asked by AnneS2 on 01 Apr 05:00

Last updated by anonymous on 03 Apr 22:10

1 Answers

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Answered by CherieS on 03 Apr 22:10

64x^2 + 16x + 1 = 0

(8x )(8x ) ( +1)( +1)

(8x+1)(8x+1)=(8x+1)^2

Check:

(8x+1)(8x+1)

(8x)(8x) (8x)(1) (1)(8x) (1)(1)

64x^2 +8x +8x +1

64x^2 +16x +1