Math

4x^ 2 +7x+3=0 Factor and solve

Asked by AnneS2 on 03 Sep 07:15

Last updated by anonymous on 04 Sep 14:13

1 Answers

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Answered by CherieS on 04 Sep 14:13

4x^ 2 +7x+3=0

(x )(4x ) ( +1)( +3)=0

(x+1) (4 x+3) = 0

Solve:

(x+1)=0

x+1-1=0-1

x=-1

Solve:

(4 x+3) = 0

4 x+3-3 = 0-3

4x=-3

4x/4=-3/4

x=-3/4