Math

3y^2 -19y+6=0

Asked by AnneS2 on 24 Apr 03:31

Last updated by anonymous on 26 Apr 22:57

1 Answers

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Answered by CherieS on 26 Apr 22:57

3y^2 -19y+6=0

(y )(3y ) ( -6)( -1)=0

(y-6)(3y-1)=0

Check:

(y-6)(3y-1)

(y)(3y) (y)(-1) (-6)(3y) (-6)(-1)

3y^2 -y -18y +6

3y^2 -19y +6