Math
3c+4u=33 6c+3u=36 Solve for each system
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Asked by
AnneS2
Last updated by
anonymous
6c+3u=36
6c-6c+3u=36-6c
3u=36-6c
3u/3=36-6c/3
u=12-2c
3c+4u=33
3c+4(12-2c)=33
3c+4(12) (4)(-2c)=33
3c+48-8c=33
48-5c=33
48-5c-48=33-48
-5c=-15
-5c/-5=-15/-5
c=3
u=12-2c
u=12-2(3)
u=12-6=6