Math 3a+5u=17 and 2a+u=9 Solve for each system Asked by AnneS2 on 18 Jul 05:32 Last updated by anonymous on 19 Jul 15:16
2a+u=9 2a-2a+u=9-2a u=9-2a 3a+5u=17 3a+5(9-2a)=17 3a+5(9) (5)(-2a)=17 3a+45-10a=17 45-7a=17 45-7a-45=17-45 -7a=-31 -7a/-7=-31/-7 a=4.43 u=9-2a u=9-2(4.43) u=9-8.86=.14