Math

3a+5u=17 and 2a+u=9 Solve for each system

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2a+u=9

2a-2a+u=9-2a

u=9-2a

3a+5u=17

3a+5(9-2a)=17

3a+5(9) (5)(-2a)=17

3a+45-10a=17

45-7a=17

45-7a-45=17-45

-7a=-31

-7a/-7=-31/-7

a=4.43

u=9-2a

u=9-2(4.43)

u=9-8.86=.14