Math

(34 k - 97 n)^2, when k = 18 and n = 5

Asked by AnneS2 on 09 Oct 04:54

Last updated by anonymous on 10 Oct 13:47

1 Answers

Log in to answer

Answered by CherieS on 10 Oct 13:47

(34 k - 97 n)^2

(34 *18 - 97 *5)^2

(612 - 97 *5)^2

(612 - 485)^2

(127)^2

16129