Math

(34 k - 97 n)^2, when k = 18 and n = 5

Asked by AnneS2 12 years ago 10/9/2013 4:54 AM

Last updated by anonymous 12 years ago 10/10/2013 1:47 PM

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Answered by CherieS 12 years ago 10/10/2013 1:47 PM

(34 k - 97 n)^2

(34 *18 - 97 *5)^2

(612 - 97 *5)^2

(612 - 485)^2

(127)^2

16129