Math
2y+5z=64 y + 7z = 68
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Asked by
AnneS2
Last updated by
anonymous
2y+5z=64 y + 7z = 68
y+7z=68
y+7z-7z=68
y=68-7z
2y+5z=64
2(68-7z)+5z=64
(2)(68) -(2)(7z)+5z=64
136-14z+5z=64
136-9z=64
136-136-9z=64-136
-9z=-72
-9z/-9=-72/-9
z=8
y=68-7z
y=86-7(8)
y=68-56
y=12