(2y^3 + 6y^2 - 7) - (4y^2 + 9) - (3y^3 - 5y^2)

Asked by AnneS2 on 23 Sep 05:57

Last updated by anonymous on 24 Sep 18:19

Answered by CherieS on 24 Sep 18:19

(2y^3+ 6y^2- 7) - (4y^2+ 9) - (3y^3- 5y^2)

2y^3+ 6y^2- 7 - 4y^2- 9 - 3y^3+ 5y^2 2y^3- 3y^3 + 6y^2 - 4y^2 + 5y^2 - 7 - y^3 + 7y^2 -7