Math
2y^2 +4y+2=0 Factor and check
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Asked by
AnneS2
Last updated by
anonymous
2y^2 +4y+2=0
2(y^2 +2y+1)=0
2 (y )(y ) ( +1)( +1=0
2(y+1)(y+1)=0
2 (y+1)^2 = 0
Check:
2(y+1)(y+1)=0
2(y)(y) (y)(1) (1)(y) (1)(1)=0
2 (y^2+ 1y +1y +1)=0
2 (y^2 +2y +1)=0
2y^2 +4y +2=0