Math

2y^2 +4y+2=0 Factor and check

Asked by
Last updated by anonymous
1 Answers
Log in to answer

2y^2 +4y+2=0

2(y^2 +2y+1)=0

2 (y )(y ) ( +1)( +1=0

2(y+1)(y+1)=0

2 (y+1)^2 = 0

Check:

2(y+1)(y+1)=0

2(y)(y) (y)(1) (1)(y) (1)(1)=0

2 (y^2+ 1y +1y +1)=0

2 (y^2 +2y +1)=0

2y^2 +4y +2=0