Math

(2x^3-7x^2+ 16) + (6x^3+ 5x^2-1)

Asked by
Last updated by anonymous
1 Answers
Log in to answer

(2x^3-7x^2+ 16) + (6x^3+ 5x^2-1)

2x^3-7x^2+ 16 + 6x^3+ 5x^2-1

2x^3+ 6x^3 -7x^2+ 5x^2 + 16-1

8x^3-2x^2+ 15