Math

(2x^3-7x^2+ 16) + (6x^3 + 5x^2-1)

Asked by AnneS2 on 15 Apr 02:55

Last updated by anonymous on 16 Apr 17:33

1 Answers

Log in to answer

Answered by CherieS on 16 Apr 17:33

=(2x^3-7x^2+ 16) + (6x^3 + 5x^2-1)

=(2x^3-7x^2+ 16) + 6x^3 + 5x^2-1

=2x^3-7x^2+ 16 + 6x^3 +5x^2-1

=2x^3+6x^3 -7x^2+5x^2 + 16-1

=8x^3 -2x^2 +15