Math 1x^2 - 9x + 20 = 0 Solve for x Asked by AnneS2 on 10 May 05:01 Last updated by anonymous on 12 May 12:09
1x^2 - 9x + 20 = 0 (x )(x ) ( -5)( -4)=0 (x-5) (x-4) = 0 Solve: (x-5)=0 x-5+5=0+5 x=5 Solve: (x-4) = 0 x-4+4=0+4 x=4