Math 1x^2 - 8x - 9 = 0 Solve for x Asked by AnneS2 on 10 May 04:59 Last updated by anonymous on 12 May 12:21
1x^2 - 8x - 9 = 0 (x )(x ) ( -9)( +1)=0 (x-9) (x+1) = 0 Solve: (x-9)=0 x-9+9=0+9 x=9 Solve: (x+1) = 0 x+1-1=0-1 x=-1