Math 1x^2 - 8x + 15 = 0 Solve for x Asked by AnneS2 on 10 May 05:00 Last updated by anonymous on 12 May 12:12
1x^2 - 8x + 15 = 0 (x )(x ) ( -5)( -3)=0 (x-5) (x-3) = 0 Solve: (x-5)=0 x-5+5=0+5 x=5 Solve: (x-3) = 0 x-3+3=0+3 x=3