Math 1x^2 - 6x + 8 = 0 Solve for x Asked by AnneS2 on 10 May 05:16 Last updated by anonymous on 11 May 21:52
1x^2 - 6x + 8 = 0 (x )(x ) ( -4)( -2)=0 (x-4)(x-2)=0 Solve: (x-4)=0 x-4+4=0+4 x=4 Solve: (x-2)=0 x-2+2=0+2 x=+2
