Math 1x^2 - 3x - 18 = 0 Solve for x Asked by AnneS2 on 10 May 05:15 Last updated by anonymous on 11 May 22:00
1x^2 - 3x - 18 = 0 (x )(x ) ( -6)( +3)=0 (x-6)(x+3)=0 Solve: (x-6)=0 x-6+6=0+6 x=6 Solve: (x+3)=0 x+3-3=0-3 x=-3
