Math 1x^2 - 3x + 2 = 0 Solve for x Asked by AnneS2 on 10 May 05:15 Last updated by anonymous on 11 May 22:03
1x^2 - 3x + 2 = 0 (x )(x ) ( -2)( -1)=0 (x-2)(x-1)=0 Solve: (x-2)=0 x-2+2=0+2 x=2 Solve: (x-1)=0 x-1+1=0+1 x=1
