Math 1x^2 - 1x - 72 = 0 Factor and solve Asked by AnneS2 on 16 Aug 05:36 Last updated by anonymous on 17 Aug 13:03
1x^2 - 1x - 72 = 0 (x )(x ) ( -9)( +8)=0 (x-9) (x+8) = 0 Solve: (x-9)=0 x-9+9=0+9 x=9 Solve: (x+8) = 0 x+8-8 = 0-8 x=-8