Math 1x^2 - 11x + 28 = 0 Solve for x Asked by AnneS2 on 10 May 05:14 Last updated by anonymous on 11 May 22:12
1x^2 - 11x + 28 = 0 (x )(x ) ( -7)( -4) (x-7)(x-4)=0 Solve: (x-7)=0 x-7+7=0+7 x=7 Solve: (x-4)=0 x-4+4=0+4 x=4
