Math

1x^2 - 11x + 28 = 0 Solve for x

Asked by AnneS2 on 10 May 05:05

Last updated by anonymous on 12 May 11:47

1 Answers

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Answered by CherieS on 12 May 11:47

1x^2 - 11x + 28 = 0

(x )(x ) ( -7)( -4)=0

(x-7) (x-4) = 0

Solve:

(x-7) =0

x-7+7=0+7

x=7

Solve:

(x-4) = 0

x-4+4=0+4

x=4