Math 1x^2 + 8x - 9 = 0 Solve for x Asked by AnneS2 on 10 May 05:19 Last updated by anonymous on 11 May 21:30
1x^2 + 8x - 9 = 0 (x )(x ) ( -1)( +9)=0 (x-1)(x+9)=0 Solve: (x-1)=0 x-1+1=0+1 x=1 Solve: (x+9)=0 x+9-9=0-9 x=-9
