Math 1x^2 + 7x - 18 = 0 Solve for x Asked by AnneS2 on 10 May 05:11 Last updated by anonymous on 12 May 11:33
1x^2 + 7x - 18 = 0 (x )(x ) ( -2)( +9) (x-2)(x+9)=0 Solve: (x-2)=0 x-2+2=0+2 x=2 Solve: (x+9)=0 x+9-9=0-9 x=-9
