Math 1x^2 + 6x - 16 = 0 Solve for x Asked by AnneS2 on 10 May 05:13 Last updated by anonymous on 11 May 22:19
1x^2 + 6x - 16 = 0 (x )(x ) ( -2)( +8)=0 (x-2)(x+8)=0 Solve: (x-2)=0 x-2+2=0+2 x=2 Solve: (x+8)=0 x+8-8=0-8 x=-8
