Math 1x^2 + 4x - 32 = 0 Factor and solve Asked by AnneS2 on 16 Aug 05:37 Last updated by anonymous on 17 Aug 13:00
1x^2 + 4x - 32 = 0 (x )(x ) ( -4)( +8)=0 (x-4) (x+8) = 0 Solve: (x-4)=0 x-4+4=0+4 x=4 Solve: (x+8) = 0 x+8-8 = 0-8 x=-8