Math

1x^2 + 3x + 2 = 0 Solve for x

Asked by AnneS2 on 10 May 04:59

Last updated by anonymous on 12 May 12:19

1 Answers

Log in to answer

Answered by CherieS on 12 May 12:19

1x^2 + 3x + 2 = 0

(x )(x ) ( +1)( +2)=0

(x+1) (x+2) = 0

Solve:

(x+1)=0

x+1-1=0-1

x=-1

Solve:

(x+2) = 0

x+2-2=0-2

x=-2