Math

1x^2 + 14x + 48 = 0 Solve for x

Asked by AnneS2 on 10 May 05:03

Last updated by anonymous on 12 May 11:56

1 Answers

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Answered by CherieS on 12 May 11:56

1x^2 + 14x + 48 = 0

(x )(x ) ( +6)( +8)=0

(x+6) (x+8) = 0

Solve:

(x+6)=0

x+6-6=0-6

x=-6

Solve:

(x+8) = 0

x+8-8=0-8

x=-8