Math 1x^2 + 13x + 36 = 0 Solve for x Asked by AnneS2 on 10 May 05:13 Last updated by anonymous on 12 May 11:16
1x^2 + 13x + 36 = 0 (x )(x ) ( +4)( +9) (x+4)(x+9)=0 Solve: (x+4)=0 x+4-4=0-4 x=-4 Solve: (x+9)=0 x+9-9=0-9 x=-9
