Math 1^3 + (7^2 + 9 - 4^2 + 8)= Asked by AnneS2 on 09 Aug 03:55 Last updated by anonymous on 10 Aug 12:22
PEMDAS=(), exponents, *, /, +, - =1^3 + (7^2 + 9 - 4^2 + 8) =1^3 + (49 + 9 - 4^2 + 8) =1^3 + (49 + 9 - 16 + 8) =1^3 + (58 - 16 + 8) =1^3 + (42 + 8) =1^3 + (50) =1 + (50) =51