Math

(1 * 4^2 - 8) - 2^3 + 4=

Asked by AnneS2 on 18 Aug 01:07

Last updated by anonymous on 20 Aug 07:09

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Answered by CherieS on 20 Aug 07:09

PEMDAS=(), exponents, *,/, +, -

=(1 * 4^2 - 8) - 2^3 + 4

=(1 * 16 - 8) - 2^3 + 4

=(16 - 8) - 2^3 + 4

=(8) - 2^3 + 4

=(8) - 8 + 4

=0+4

=4