Math

-32x^2 -92x - 56 = 0 Solve for x

Asked by AnneS2 on 17 May 05:13

Last updated by anonymous on 19 May 11:20

1 Answers

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Answered by CherieS on 19 May 11:20

-32x^2 -92x - 56 = 0

-4(8x^2+23x+14)=0

-4(x )(8x ) ( +2)( +7)=0

-4 (x+2) (8 x+7) = 0

Solve:

-4 (x+2)=0

(-4)(x) (-4)(+2)=0

-4x-8=0

-4x-8+8=0+8

-4x=8

-4x/-4=8/-4

x=-2

Solve:

-4(8 x+7) = 0

(-4)(8x) (-4)(+7)=0

-32x-28=0

-32x-28+28=0+28

-32x=28

-32x/-32=28/-32

x=-7/8