Math

-1x^2 + 3x + 10 = 0 Solve for x

Asked by AnneS2 on 10 May 05:02

Last updated by anonymous on 12 May 12:05

1 Answers

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Answered by CherieS on 12 May 12:05

-1x^2 + 3x + 10 = 0

-1(x^2-3x-10)=0

-1(x )(x ) ( -5)( +2)

-1(x-5) (x+2) = 0

Solve:

-1(x-5)=0

(-1)(x) (-1)(-5)=0

-1x+5=0

-1x+5-5=0-5

-1x=-5

-1x/-1=-5/-1

x=5

Solve:

-1(x+2) = 0

(-1)(x) (-1)(+2)=0

-1x-2=0

-1x-2+2=0+2

-1x=2

-1x/-1=2/-1

x=-2