Math
-1x^2 + 1x + 2 = 0 Solve for x
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Asked by
AnneS2
Last updated by
anonymous
-1x^2 + 1x + 2 = 0
-1(x^2-1x-2)=0
-1(x )(x ) ( -2)( +1)=0
-1(x-2) (x+1) = 0
Solve:
-1(x-2)=0
(-1)(x) (-1)(-2)=0
-1x+2=0
-1x+2-2=0-2
-1x=-2
-1x/-1=-2/-1
x=2
Solve:
-1(x+1) = 0
(-1)(x) (-1)(+1)=0
-1x-1=0
-1x-1+1=0+1
-1x=1
-1x/-1=1/-1
x=-1