Math

-1x^2 + 16x - 63 = 0 Factor and solve

Asked by AnneS2 on 16 Aug 05:32

Last updated by anonymous on 17 Aug 13:34

1 Answers

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Answered by CherieS on 17 Aug 13:34

-1x^2 + 16x - 63 = 0

-1(x^2-16x+63)=0

-1(x )(x ) ( -9)( -7)=0

-1(x-9) (x-7) = 0

Solve:

-1(x-9)=0

-1(x) (-1)(-9)=0

-1x+9=0

-1x+9-9=0-9

-1x=-9

-1x/-1=-9/-1

x=9

Solve:

-1(x-7) = 0

-1(x) (-1)(-7) = 0

-1x+7=0

-1x+7-7=0-7

-1x=7

-1x/-1=7/-1

x=-7