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Enthalpy of Neutralisation
Results table
Volume of 1M HCL, HNO3, H2SO4 - cm3
+- 0.05 Temperature of 1M HCL - °C
+
+- 0.5 °C Temperature of 0.5M H2SO4 - °C
+
- 00 3¬1.0 30.0 31.0
- 00 32.0 31.0 33.0
- 00 33.0 31.5 35.0
- 00 34.0 32.0 36.0
- 00 35.0 31.5 37.0
- 00 36.0 31.5 38.0
- 00 35.0 31.5 37.0
- 00 34.0 31.5 36.0
- 00 34.0 31.5 35.0
- 00 33.0 31.5 35.0
- 00 33.0 31.5 35.0
To measure the heat of neutralization - the following formula was used:
Q = mc Ä T
Q = Energy in (joules, J)
m = density of solution = density of water
(assumption: 1 ml = 1grammes because of density).
c = specific heat capacity ( Jg-1°C-1), the energy required to raise the temperature of 1g of a substance by 1°C.
Calculation for experiment 1 - 1M HCL
Q = mc Ä T
m = 50g
c = 4.18 Jg-1°C-1
Ä T = 31-36
= -5°C
Q = 50 x 4.18 x -5
= -1045 J
The enthalpy change for 25cm3 = -1045 j
The enthalpy change for 1000cm3 = -1045 x 1000
25
= - 41800 J
= - 41.8 kJ
Uncertainties
Burette =± 0.05 %
Thermometer =± 0.5 %
Pipette = ± 0.1 %
Calculation of Uncertainties...
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