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Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid.
Aim: Determine a Rate Equation between reaction of potassium permanganate and oxalic acid.
Experiment Procedure:
Refer to worksheet enclosed.
Data Collection:
Mass of beaker: 32.17g ± 0.005g
Mass of beaker + (COOH)2: 63.67g ± 0.005g
Volume of (COOH)2: 500ml ± 0.2ml
Reagents Experiment 1Volume /mL ± 0.1mL Experiment 2Volume /mL ± 0.1mL Experiment 3Volume /mL ± 0.1mL
H2C2O4 20.00 20.00 10.00
KMnO4 10.00 5.00 10.00
H2O 0.00 5.00 10.00
Scale of bruette: 0.1ml
Scale of balance: 0.01g
Results:
Experiment 1 Experiment 2 Experiment 3
Time ± 0.2s 00:06:54 00:07:21 00:11:57
(hour: minute: second) 00:07:03 00:07:40 00:12:40
00:07:11 00:07:31 00:12:31
Systematic error of time is ± 0.05s. However humans can only resond up to ± 0.2s.
Data Processing and Presentation:
Experiment 1 Experiment 2 Experiment 3
Time (s) ± 0.2s 414 441 717
423 460 760
431 451 751
Average time (s) 422.7 450.7 742.7
Mass of (COOH)2: (63.67 - 32.17)g ± (0.005 + 0.005)g
= 31.50g ± 0.01g
Starting concentration of (COOH)2 = moles / volume
= (31.50 / 126.07) / (500 / 1000)
= 0.4997 mol dm-3
Starting concentration of KMnO4 : = moles / volume
= 0.02 mol dm-3
[KMnO4] [(COOH)2]
r1 (0.02 * 10 / 1000 / 30 / 1000) (0.5 * 20 / 1000 / 30 / 1000)
r2 (0.02 * 5 / 1000 / 30 / 1000) (0.5 * 20 / 1000 / 30 / 1000)
r3 (0.02 * 10 / 1000 / 30 / 1000) (0.5 * 10 / 1000 / 30 / 1000)
Rate = k [KMnO4]x [(COOH)2]y
r = k [KMnO...
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