Reaction rate Essay | Essay

This student essay consists of approximately 4 pages of analysis of Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid..

Reaction rate Essay | Essay

This student essay consists of approximately 4 pages of analysis of Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid..
This section contains 1,001 words
(approx. 4 pages at 300 words per page)
Buy the Student Essay on Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid.

Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid.

Summary: Determining a Rate Equation between reaction of potassium permanganate and oxalic acid.
- Data Collection, Data Processing and Presentation, Conclusion and Evaluation

Aim: Determine a Rate Equation between reaction of potassium permanganate and oxalic acid.

Experiment Procedure:

Refer to worksheet enclosed.

Data Collection:

Mass of beaker: 32.17g ± 0.005g

Mass of beaker + (COOH)2: 63.67g ± 0.005g

Volume of (COOH)2: 500ml ± 0.2ml

Reagents Experiment 1Volume /mL ± 0.1mL Experiment 2Volume /mL ± 0.1mL Experiment 3Volume /mL ± 0.1mL

H2C2O4 20.00 20.00 10.00

KMnO4 10.00 5.00 10.00

H2O 0.00 5.00 10.00

Scale of bruette: 0.1ml

Scale of balance: 0.01g

Results:

Experiment 1 Experiment 2 Experiment 3

Time ± 0.2s 00:06:54 00:07:21 00:11:57

(hour: minute: second) 00:07:03 00:07:40 00:12:40

00:07:11 00:07:31 00:12:31

Systematic error of time is ± 0.05s. However humans can only resond up to ± 0.2s.

Data Processing and Presentation:

Experiment 1 Experiment 2 Experiment 3

Time (s) ± 0.2s 414 441 717

423 460 760

431 451 751

Average time (s) 422.7 450.7 742.7

Mass of (COOH)2: (63.67 - 32.17)g ± (0.005 + 0.005)g

= 31.50g ± 0.01g

Starting concentration of (COOH)2 = moles / volume

= (31.50 / 126.07) / (500 / 1000)

= 0.4997 mol dm-3

Starting concentration of KMnO4 : = moles / volume

= 0.02 mol dm-3

[KMnO4] [(COOH)2]

r1 (0.02 * 10 / 1000 / 30 / 1000) (0.5 * 20 / 1000 / 30 / 1000)

r2 (0.02 * 5 / 1000 / 30 / 1000) (0.5 * 20 / 1000 / 30 / 1000)

r3 (0.02 * 10 / 1000 / 30 / 1000) (0.5 * 10 / 1000 / 30 / 1000)

Rate = k [KMnO4]x [(COOH)2]y

r = k [KMnO...

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(approx. 4 pages at 300 words per page)
Buy the Student Essay on Determine a Rate Equation between Reaction of Potassium Permanganate and Oxalic Acid.
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