penetrating its uppermost layer. Thus, if dyed
fabrics are examined by the spectroscope, the same
appearances are generally observed as with the solution
of the corresponding colouring matters. An absorption
spectrum is in each case obtained, but the one from
the solution is the purer, for it does not contain
the mixed white light reflected from the surfaces
of coloured objects. Let us now take an example.
We will take a cylinder glass full of picric acid
in water, and of a yellow colour. Now when I
pass white light through that solution and examine
the emerging light, which looks, to my naked eye,
yellow, I find by the spectroscope that what has taken
place is this: the blue part of the spectrum is
totally extinguished as far as G and 2/3 of F. That
is all. Then why, say you, does that liquid look
yellow if all the rest of those rays pass through
and enter the eye, namely, the blue-green with a trifle
of blue, the green, yellow, orange, and red?
The reason is this: we have already seen that
the colours complementary to, and so producing white
light with red, are green and greenish-blue or bluish-green.
Hence these cancel, so to say, and we only see yellow.
We do not see a pure yellow, then, in picric acid,
but yellow with a considerable amount of white.
Here is a piece of scarlet paper. Why does it
appear scarlet? Because from the white light
falling upon it, it practically absorbs all the rays
of the spectrum except the red and orange ones, and
these it reflects. If this be so, then, and we
take our spectrum band of perfectly pure colours and
pass our strip of scarlet paper along that variously
coloured band of light, we shall be able to test the
truth of several statements I have made as to the
nature of colour. I have said colour is only
an impression, and not a reality; and that it does
not exist apart from light. Now, I can show you
more, namely, that the colour of the so-called coloured
object is entirely dependent on the existence in the
light of the special coloured rays which it radiates,
and that this scarlet paper depends on the red light
of the spectrum for the existence of its redness.
On passing the piece of scarlet paper along the coloured
band of light, it appears red only when in the red
portion of the spectrum, whilst in the other portions,
though it is illumined, yet it has no colour, in fact
it looks black. Hence what I have said is true,
and, moreover, that red paper looks red because, as
you see, it absorbs and extinguishes all the rays of
the spectrum but the red ones, and these it radiates.
A bright green strip of paper placed in the red has
no colour, and looks black, but transferred to the
pure green portion it radiates that at once, does not
absorb it as it did the red, and so the green shines
out finely. I have told you that sodium salts
give to a colourless flame a fine monochromatic or
pure yellow colour. Now, if this be so, and if
all the light available in this world were of such
a character, then such a colour as blue would be unknown.