An Elementary Course in Synthetic Projective Geometry eBook

This eBook from the Gutenberg Project consists of approximately 113 pages of information about An Elementary Course in Synthetic Projective Geometry.

An Elementary Course in Synthetic Projective Geometry eBook

This eBook from the Gutenberg Project consists of approximately 113 pages of information about An Elementary Course in Synthetic Projective Geometry.

In the same manner the tangent at S may be constructed.

62.  Determination of the locus. We now show that it is possible to assign arbitrarily the position of three points, _A__, __B__, and __C__, on the locus (besides the points __S__ and __S’__); but, these three points being chosen, the locus is completely determined._

63. This statement is equivalent to the following: 

Given three pairs of corresponding rays in two projective pencils, it is possible to find a ray of one which corresponds to any ray of the other.

64. We proceed, then, to the solution of the fundamental

PROBLEM:  Given three pairs of rays, _aa’__, __bb’__, and __cc’__, of two protective pencils, __S__ and __S’__, to find the ray __d’__ of __S’__ which corresponds to any ray __d__ of __S__._

[Figure 12]

FIG. 12

Call A the intersection of aa’, B the intersection of bb’, and C the intersection of cc’ (Fig. 12).  Join AB by the line u, and AC by the line u’.  Consider u as a point-row perspective to S, and u’ as a point-row perspective to S’. u and u’ are projectively related to each other, since S and S’ are, by hypothesis, so related.  But their point of intersection A is a self-corresponding point, since a and a’ were supposed to be corresponding rays.  It follows (§ 52) that u and u’ are in perspective position, and that lines through corresponding points all pass through a point M, the center of perspectivity, the position of which will be determined by any two such lines.  But the intersection of a with u and the intersection of c’ with u’ are corresponding points on u and u’, and the line joining them is clearly c itself.  Similarly, b’ joins two corresponding points on u and u’, and so the center M of perspectivity of u and u’ is the intersection of c and b’.  To find d’ in S’ corresponding to a given line d of S we note the point L where d meets u.  Join L to M and get the point N where this line meets u’. L and N are corresponding points on u and u’, and d’ must therefore pass through N.  The intersection P of d and d’ is thus another point on the locus.  In the same manner any number of other points may be obtained.

65. The lines u and u’ might have been drawn in any direction through A (avoiding, of course, the line a for u and the line a’ for u’), and the center of perspectivity M would be easily obtainable; but the above construction furnishes a simple and instructive figure.  An equally simple one is obtained by taking a’ for u and a for u’.

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An Elementary Course in Synthetic Projective Geometry from Project Gutenberg. Public domain.