Blasting gelatine (90 per cent. nitro-glycerine and nitro-cellulose) 392 Ammonite (60 per cent.  Am(NO_{3}) and 10 per cent. nitro-naphthalene) 310 Gelignite (60 per cent. nitro-gelatine and gun-cotton) 306 Roburite (AmNO_{3} and chloro-nitro-benzol) 294 No. 1 dynamite (75 per cent. nitro-gelatine) 264 Stonite (68 per cent. nitro-gelatine and 32 per cent. wood-meal) 253 Gun-cotton 234 Tonite (gun-cotton and nitrates) 223 Carbonite (25 per cent. nitro-gelatine, 40 per cent. wood-meal,
  and 30 per cent. nitrates) 198
Securite (KNO_{3} and nitro-benzol) 183 Gunpowder 143

Calculation of the Volume of Gas Evolved in an Explosive Reaction.—­The volume of gas evolved in an explosive reaction may be calculated, but only when they are simple and stable products, such calculations being made at 0 deg. and 760 mm.  Let it be required, for example, to determine the volume of gas evolved by 1 gram-molecule of nitro-glycerine.  The explosive reaction of nitro-glycerine may be represented by the equation.

C_{3}H_{5}O_{3}(NO_{2})_{3} = 3CO_{2} + 2-1/2H_{2}O + 1-1/2N_{2} + 1/4O_{2}
By weight       227         =  132    +   45        +   42       +    8
By volume         2         =    3    +    2-1/2    +    1-1/2   +    1/4

The weights of the several products of the above reactions are calculated by multiplying their specific gravities by the weight of 1 litre of hydrogen at 0 deg.  C. and 760 mm. (0.0896 grm).  Thus,

One litre of CO_{2} = 22 x .0896 = 1.9712 grm.
     " H_{2}O = 9 x " = 0.8064 "
     " N_{2} = 14 x " = 1.2544 "
     " O_{2} = 16 x " = 1.4336 "

The volume of permanent gases at 0 deg. and 760 mm. is constant, and assuming the gramme as the unit of mass, is found to be 22.32 litres.  Thus:—­

Volume of 44 of CO_{2}, at 0 deg. and 760 mm. = 44/1.9712 = 22.32 litres.
          18 " H_{2}O " " = 18/0.8044 = 22.32 "
          28 " N_{2} " " = 28/1.2544 = 22.32 "
          32 " O_{2} " " = 32/1.4366 = 22.32 "

Therefore

132 grms. of CO_{2} at 0 deg.  C and 760 mm. = 22.32 x 3 = 66.96 litres. 45 " H_{2}O " " = 22.32 x 2-1/2 = 55.80 " 42 " N_{2} " " = 22.32 x 1-1/2 = 33.48 "
  8 " O_{2} " " = 22.32 x 1/4 = 5.58 "
          
                                              ____________

161.82 "
Therefore 1 gram-molecule or 227 grms. of nitro-glycerine when exploded, produces 161.82 litres of gas at 0 deg.  C and 760 mm.